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Parallel Plate Capacitor Calculator

Tested

Capacitance of two parallel plates.

Tested, not yet published. The formula for this calculator is implemented and passes its automated checks. This page stays non-indexable until it is reviewed and published.

cm²
mm

Results

Enter your values and press Calculate. Results appear here.

  • • Result

Quick answer

Capacitance C = ε₀ εr A ÷ d, with ε₀ = 8.8541878128 × 10⁻¹² F/m. Plates of 10 cm² separated by 1 mm in vacuum (εr = 1) give 8.8542 pF.

Enter the plate area, separation and relative permittivity. The calculator returns the capacitance. Use this parallel plate capacitor calculator to check your own figures.

Related tools: Voltage Divider Calculator: Output voltage of a two-resistor divider. RLC Impedance Calculator: Impedance and phase angle of a series RLC circuit. RMS Voltage Calculator: Convert between RMS, peak and peak-to-peak voltage of a sine wave.

How to use the Parallel Plate Capacitor Calculator

  1. Enter plate area (cm²) (above 0).
  2. Enter plate separation (mm) (above 0).
  3. Enter relative permittivity εr (above 0). It starts at 1.
  4. Press Calculate to see the result, and use Reset to start again.
Inputs of the Parallel Plate Capacitor Calculator
InputWhat to enterAllowed values
Plate areaA number, in cm²> 0
Plate separationA number, in mm> 0
Relative permittivity εrA number> 0, starts at 1

Formula and method

Formula

C = ε₀ εr A ÷ d, ε₀ = 8.8541878128×10⁻¹² F/m

IEEE-754 double precision; shown to the decimals indicated.

Ignores fringing fields, which matter when the gap is not small compared with the plates.

Worked examples

These examples are verified: each one is an automated test case that the live calculator must reproduce exactly.

Example 1

Inputs: Plate area = 10; Plate separation = 1; Relative permittivity εr = 1.

Results of example 1
ResultValue
Capacitance8.8542 pF

Example 2

Inputs: Plate area = 25; Plate separation = 0.5; Relative permittivity εr = 4.5.

Results of example 2
ResultValue
Capacitance199.2192 pF

Example 3

Inputs: Plate area = 100; Plate separation = 2; Relative permittivity εr = 2.2.

Results of example 3
ResultValue
Capacitance97.3961 pF

The first line is the headline result (capacitance). IEEE-754 double precision; shown to the decimals indicated.

Scaling

Capacitance rises with area and with permittivity and falls with separation. A dielectric with εr = 4 quadruples the capacitance to about 35.4 pF. Halving the gap doubles it.

Validity

The formula assumes the separation is much smaller than the plate size, so edge (fringing) effects are small. Real capacitors also have a breakdown voltage that limits how thin the dielectric can be.

How the result changes with plate area

Holding every other input at the first worked example, this table changes only plate area. It shows how sensitive the answer is to that one value; each row was produced by running this calculator.

How the result changes with plate area
Plate areaCapacitance
54.4271 pF
108.8542 pF
2017.7084 pF
4035.4168 pF

What happens with invalid input

These messages are produced by the calculator itself, so you know what to fix.

  • Plate area: entering "0" shows "Plate area must be greater than 0." beside that field and no result.
  • Relative permittivity εr: entering "0" shows "Relative permittivity εr must be greater than 0." beside that field and no result.

Choosing between the Parallel Plate Capacitor Calculator and similar calculators

Each row shows what a related calculator on this site asks for and what it returns, so you can pick the one that matches your question.

Choosing between the Parallel Plate Capacitor Calculator and similar calculators
CalculatorYou enterIt returns
[Voltage Divider Calculator](/engineering/voltage-divider-calculator/)input voltage, r1 and r2Output voltage
[RLC Impedance Calculator](/engineering/rlc-impedance-calculator/)resistance, inductance and capacitanceImpedance
[RMS Voltage Calculator](/engineering/rms-voltage-calculator/)i know the and voltageRMS voltage
[Current Divider Calculator](/engineering/current-divider-calculator/)total current, r1 and r2Current through R1
[Inductive Reactance Calculator](/engineering/inductor-reactance-calculator/)inductance and frequencyInductive reactance

Background: electrical circuits

Ohm's law links voltage, current and resistance: V = I × R, so I = V ÷ R and R = V ÷ I. Power is P = V × I, which also equals I² × R and V² ÷ R.

These relations hold for ohmic components, where resistance is constant. Diodes and transistors are non-linear, and in AC circuits with reactive parts impedance (Z) takes the place of resistance. Check component ratings and local electrical code before relying on any calculation.

Assumptions and limitations

  • Valid when d is much smaller than the plate size

Use results as engineering estimates and check them against the governing standards, safety factors and a qualified engineer's judgement before relying on them.

If a required value is empty, not a number, or outside its allowed range, the form marks that field with a message and shows no result instead of a misleading number. The automated checks deliberately try invalid entries for plate area and relative permittivity εr to confirm this.

Frequently asked questions

What is permittivity?

A material's ability to store electric energy in a field.

What is a picofarad?

A picofarad is 10⁻¹² farad, so the 8.8542 pF in the example is 0.0000000000088542 F.

How can I increase capacitance?

Increase area or reduce the gap.

What does the Parallel Plate Capacitor Calculator calculate?

Capacitance of two parallel plates. It returns Capacitance.

What formula does the Parallel Plate Capacitor Calculator use?

C = ε₀ εr A ÷ d, ε₀ = 8.8541878128×10⁻¹² F/m. Ignores fringing fields, which matter when the gap is not small compared with the plates.

What do I need to enter in the parallel Plate Capacitor Calculator?

You enter Plate area (cm²), Plate separation (mm) and Relative permittivity εr.

How is the result rounded or limited?

IEEE-754 double precision; shown to the decimals indicated. Valid when d is much smaller than the plate size.

What is an example of a parallel Plate Capacitor result?

With plate area 10, plate separation 1 and relative permittivity εr 1, the capacitance is 8.8542 pF.

Where does the method come from?

The method follows: CODATA 2018 / SI exact constants.

Can I rely on this calculator for a decision?

Use results as engineering estimates and check them against the governing standards, safety factors and a qualified engineer's judgement before relying on them. For this calculator in particular: Valid when d is much smaller than the plate size.

Sources

  • CODATA 2018 / SI exact constants

Content last reviewed 2026-11-04. Formulas and worked examples are checked by automated tests against independently computed values.